3.25.74 \(\int \frac {1}{(1-2 x)^{5/2} \sqrt {3+5 x}} \, dx\)

Optimal. Leaf size=45 \[ \frac {20 \sqrt {5 x+3}}{363 \sqrt {1-2 x}}+\frac {2 \sqrt {5 x+3}}{33 (1-2 x)^{3/2}} \]

________________________________________________________________________________________

Rubi [A]  time = 0.00, antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {45, 37} \begin {gather*} \frac {20 \sqrt {5 x+3}}{363 \sqrt {1-2 x}}+\frac {2 \sqrt {5 x+3}}{33 (1-2 x)^{3/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/((1 - 2*x)^(5/2)*Sqrt[3 + 5*x]),x]

[Out]

(2*Sqrt[3 + 5*x])/(33*(1 - 2*x)^(3/2)) + (20*Sqrt[3 + 5*x])/(363*Sqrt[1 - 2*x])

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n +
1))/((b*c - a*d)*(m + 1)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*Simplify[m + n + 2])/((b*c - a*d)*(m + 1)), Int[(a + b*x)^Simplify[m +
1]*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && ILtQ[Simplify[m + n + 2], 0] &&
 NeQ[m, -1] &&  !(LtQ[m, -1] && LtQ[n, -1] && (EqQ[a, 0] || (NeQ[c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && (
SumSimplerQ[m, 1] ||  !SumSimplerQ[n, 1])

Rubi steps

\begin {align*} \int \frac {1}{(1-2 x)^{5/2} \sqrt {3+5 x}} \, dx &=\frac {2 \sqrt {3+5 x}}{33 (1-2 x)^{3/2}}+\frac {10}{33} \int \frac {1}{(1-2 x)^{3/2} \sqrt {3+5 x}} \, dx\\ &=\frac {2 \sqrt {3+5 x}}{33 (1-2 x)^{3/2}}+\frac {20 \sqrt {3+5 x}}{363 \sqrt {1-2 x}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.01, size = 27, normalized size = 0.60 \begin {gather*} -\frac {2 \sqrt {5 x+3} (20 x-21)}{363 (1-2 x)^{3/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/((1 - 2*x)^(5/2)*Sqrt[3 + 5*x]),x]

[Out]

(-2*Sqrt[3 + 5*x]*(-21 + 20*x))/(363*(1 - 2*x)^(3/2))

________________________________________________________________________________________

IntegrateAlgebraic [A]  time = 0.08, size = 38, normalized size = 0.84 \begin {gather*} \frac {2 (5 x+3)^{3/2} \left (\frac {15 (1-2 x)}{5 x+3}+2\right )}{363 (1-2 x)^{3/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[1/((1 - 2*x)^(5/2)*Sqrt[3 + 5*x]),x]

[Out]

(2*(3 + 5*x)^(3/2)*(2 + (15*(1 - 2*x))/(3 + 5*x)))/(363*(1 - 2*x)^(3/2))

________________________________________________________________________________________

fricas [A]  time = 1.63, size = 33, normalized size = 0.73 \begin {gather*} -\frac {2 \, {\left (20 \, x - 21\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{363 \, {\left (4 \, x^{2} - 4 \, x + 1\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1-2*x)^(5/2)/(3+5*x)^(1/2),x, algorithm="fricas")

[Out]

-2/363*(20*x - 21)*sqrt(5*x + 3)*sqrt(-2*x + 1)/(4*x^2 - 4*x + 1)

________________________________________________________________________________________

giac [A]  time = 1.12, size = 39, normalized size = 0.87 \begin {gather*} -\frac {2 \, {\left (4 \, \sqrt {5} {\left (5 \, x + 3\right )} - 33 \, \sqrt {5}\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5}}{1815 \, {\left (2 \, x - 1\right )}^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1-2*x)^(5/2)/(3+5*x)^(1/2),x, algorithm="giac")

[Out]

-2/1815*(4*sqrt(5)*(5*x + 3) - 33*sqrt(5))*sqrt(5*x + 3)*sqrt(-10*x + 5)/(2*x - 1)^2

________________________________________________________________________________________

maple [A]  time = 0.00, size = 22, normalized size = 0.49 \begin {gather*} -\frac {2 \sqrt {5 x +3}\, \left (20 x -21\right )}{363 \left (-2 x +1\right )^{\frac {3}{2}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(-2*x+1)^(5/2)/(5*x+3)^(1/2),x)

[Out]

-2/363*(5*x+3)^(1/2)*(20*x-21)/(-2*x+1)^(3/2)

________________________________________________________________________________________

maxima [A]  time = 1.14, size = 48, normalized size = 1.07 \begin {gather*} \frac {2 \, \sqrt {-10 \, x^{2} - x + 3}}{33 \, {\left (4 \, x^{2} - 4 \, x + 1\right )}} - \frac {20 \, \sqrt {-10 \, x^{2} - x + 3}}{363 \, {\left (2 \, x - 1\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1-2*x)^(5/2)/(3+5*x)^(1/2),x, algorithm="maxima")

[Out]

2/33*sqrt(-10*x^2 - x + 3)/(4*x^2 - 4*x + 1) - 20/363*sqrt(-10*x^2 - x + 3)/(2*x - 1)

________________________________________________________________________________________

mupad [B]  time = 0.19, size = 34, normalized size = 0.76 \begin {gather*} \frac {\sqrt {5\,x+3}\,\left (\frac {20\,x}{363}-\frac {7}{121}\right )}{x\,\sqrt {1-2\,x}-\frac {\sqrt {1-2\,x}}{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((1 - 2*x)^(5/2)*(5*x + 3)^(1/2)),x)

[Out]

((5*x + 3)^(1/2)*((20*x)/363 - 7/121))/(x*(1 - 2*x)^(1/2) - (1 - 2*x)^(1/2)/2)

________________________________________________________________________________________

sympy [B]  time = 2.86, size = 177, normalized size = 3.93 \begin {gather*} \begin {cases} \frac {100 \sqrt {10} \left (x + \frac {3}{5}\right )}{3630 \sqrt {-1 + \frac {11}{10 \left (x + \frac {3}{5}\right )}} \left (x + \frac {3}{5}\right ) - 3993 \sqrt {-1 + \frac {11}{10 \left (x + \frac {3}{5}\right )}}} - \frac {165 \sqrt {10}}{3630 \sqrt {-1 + \frac {11}{10 \left (x + \frac {3}{5}\right )}} \left (x + \frac {3}{5}\right ) - 3993 \sqrt {-1 + \frac {11}{10 \left (x + \frac {3}{5}\right )}}} & \text {for}\: \frac {11}{10 \left |{x + \frac {3}{5}}\right |} > 1 \\- \frac {100 \sqrt {10} i \left (x + \frac {3}{5}\right )}{3630 \sqrt {1 - \frac {11}{10 \left (x + \frac {3}{5}\right )}} \left (x + \frac {3}{5}\right ) - 3993 \sqrt {1 - \frac {11}{10 \left (x + \frac {3}{5}\right )}}} + \frac {165 \sqrt {10} i}{3630 \sqrt {1 - \frac {11}{10 \left (x + \frac {3}{5}\right )}} \left (x + \frac {3}{5}\right ) - 3993 \sqrt {1 - \frac {11}{10 \left (x + \frac {3}{5}\right )}}} & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1-2*x)**(5/2)/(3+5*x)**(1/2),x)

[Out]

Piecewise((100*sqrt(10)*(x + 3/5)/(3630*sqrt(-1 + 11/(10*(x + 3/5)))*(x + 3/5) - 3993*sqrt(-1 + 11/(10*(x + 3/
5)))) - 165*sqrt(10)/(3630*sqrt(-1 + 11/(10*(x + 3/5)))*(x + 3/5) - 3993*sqrt(-1 + 11/(10*(x + 3/5)))), 11/(10
*Abs(x + 3/5)) > 1), (-100*sqrt(10)*I*(x + 3/5)/(3630*sqrt(1 - 11/(10*(x + 3/5)))*(x + 3/5) - 3993*sqrt(1 - 11
/(10*(x + 3/5)))) + 165*sqrt(10)*I/(3630*sqrt(1 - 11/(10*(x + 3/5)))*(x + 3/5) - 3993*sqrt(1 - 11/(10*(x + 3/5
)))), True))

________________________________________________________________________________________